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When there are N numbers and N is too large to do O(N^2) 
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If the order of the numbers is meaningless and the number type is M, which is much less than N 
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Creating a frequency table by type can reduce the amount of calculations. 
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For any pair of two choices of N numbers, the case where two have the same value is counted 
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A naive loop is O(N^2) 
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Count the frequencies and for each value frequency n trigonometric number . - This would be O(N)
 
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