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Thoughts.
- If you actually rearrange and check, etc., you obviously won’t be able to do it in time, so some kind of saving is necessary.
- When the side is odd, all letters except the center are even or have even numbers; when the side is even, all letters have even numbers.
- I’m just trying to determine if it exists or not, so why not just count the frequency and see if it’s even or odd?
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Official Explanation
- Overlooking the problem condition, it is a palindrome, even vertically.
- The same case can be made for whether the vertical is odd or even, and the number of letters needed for one, two, or four can be determined.
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